Pure Mathematics — Second: Differential & Integral Calculus · Mathematics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 44 questions on this lesson, each with an explanation.
Find the inflection point of the curve f(x) = x³ − 3x² + 2.
A(1, 0)
B(−1, −2)
C(2, −2)
D(0, 2)
Show answer and explanation
Correct answer: (A) (1, 0)
Explanation: Step 1: First derivative: f'(x) = 3x² − 6x
Step 2: Second derivative: f''(x) = 6x − 6
Step 3: Set f''(x) = 0: 6x − 6 = 0, so x = 1
Step 4: f''(x) changes sign from negative (x less than 1) to positive (x greater than 1), so an inflection point exists
Step 5: y-value: f(1) = 1 − 3 + 2 = 0
∴ The inflection point is (1, 0)
Question 2Easy
Using the second derivative test, classify the critical point of f(x) = x² − 10x + 1.
Aneither
Blocal minimum
Clocal maximum
Dinflection point
Show answer and explanation
Correct answer: (B) local minimum
Explanation: Step 1: f'(x) = 2x − 10 = 0 ∴ x = 5.
Step 2: f''(x) = 2.
Step 3: f''(5) = 2 is positive, so by the second derivative test x = 5 is a local minimum.
∴ Local minimum
Question 3Easy
At which value of x does the curve f(x) = x³ − 6x² + 5x have an inflection point?
Ax = 3
Bx = 1
Cx = 2
Dx = 0
Show answer and explanation
Correct answer: (C) x = 2
Explanation: Step 1: f'(x) = 3x² − 12x + 5
Step 2: f''(x) = 6x − 12
Step 3: Set f''(x) = 0: 6x − 12 = 0, so x = 2
Step 4: f''(x) changes sign from negative to positive at x = 2, so it is an inflection point
∴ x = 2
Question 4Medium
On which interval is the curve f(x) = −x³ + 3x² convex upward?
A]−∞, 1[
B]−∞, 0[
C]1, ∞[
D]0, ∞[
Show answer and explanation
Correct answer: (C) ]1, ∞[
Explanation: Step 1: f'(x) = −3x² + 6x
Step 2: f''(x) = −6x + 6
Step 3: The curve is convex upward where f''(x) less than 0: −6x + 6 less than 0, so −6x less than −6, giving x greater than 1
∴ The curve is convex upward on ]1, ∞[
Question 5Medium
For the function f where f(x) = 2x³ + 3x² − 12x, on the interval ]−2, −1/2[ the curve of f is ..........
Adecreasing and convex upward
Bincreasing and convex upward
Cdecreasing and convex downward
Dincreasing and convex downward
Show answer and explanation
Correct answer: (A) decreasing and convex upward
Explanation: Step 1: f′(x) = 6x² + 6x − 12 = 6(x + 2)(x − 1) < 0 on ]−2, 1[, so f is decreasing on ]−2, −1/2[.
Step 2: f″(x) = 12x + 6 < 0 when x < −1/2, so the curve is convex upward there.
∴ decreasing and convex upward (f″ < 0 means convex upward, f″ > 0 means convex downward).
Question 6Medium
Find the measure of the angle that the tangent at the inflection point of the curve f(x) = x³ − 6x² + 11x − 6 makes with the positive direction of the x-axis.
Aπ/4
B3π/4
Cπ/3
D2π/3
Show answer and explanation
Correct answer: (B) 3π/4
Explanation: Step 1: f′(x) = 3x² − 12x + 11 and f″(x) = 6x − 12.
Step 2: f″(x) = 0 at x = 2 and f″ changes sign there, so the inflection point is at x = 2.
Step 3: Slope of the tangent there: f′(2) = 12 − 24 + 11 = −1.
Step 4: tan θ = −1 with θ between 0 and π, so θ = 3π/4.
Step 5: The angle is 3π/4.
Question 7Medium
Use the second derivative test to find the local maximum value of f(x) = x³ − 3x² − 24x + 5.
A−75
B−21
C33
D57
Show answer and explanation
Correct answer: (C) 33
Explanation: Step 1: f′(x) = 3x² − 6x − 24 = 3(x − 4)(x + 2), so f′(x) = 0 at x = −2 and x = 4.
Step 2: f″(x) = 6x − 6.
Step 3: f″(−2) = −18, which is negative, so f(−2) is a local maximum value; f″(4) = 18 is positive, so f(4) is a local minimum value.
Step 4: f(−2) = −8 − 12 + 48 + 5 = 33.
Step 5: The local maximum value is 33.
Question 8Hard
The curve of f(x) = x³ + ax² + bx has an inflection point at (1, −1). Find a + b.
A−4
B0
C−2
D2
Show answer and explanation
Correct answer: (C) −2
Explanation: Step 1: f''(x) = 6x + 2a = 0 at x = 1 ⇒ a = −3.
Step 2: f(1) = 1 − 3 + b = −1 ⇒ b = 1, so a + b = −2.
∴ −2
Question 9Hard
The increasing, decreasing and convexity table of a function f shows: f′(x) > 0 on ]−∞, −1[ and on ]1, ∞[, f′(x) < 0 on ]−1, 1[, f″(x) < 0 on ]−∞, 0[, f″(x) > 0 on ]0, ∞[, a local maximum value 3 and a local minimum value −1. Then f(x) = ..........
Ax³ − 3x + 1
B3x − x³ + 1
Cx³ + 3x + 1
Dx³ − 3x − 1
Show answer and explanation
Correct answer: (A) x³ − 3x + 1
Explanation: Step 1: f′ changes from + to − at x = −1 and from − to + at x = 1, so the critical points are ±1; x³ + 3x + 1 has f′ = 3x² + 3 > 0 and no critical points.
Step 2: x³ − 3x + 1: f′ = 3x² − 3 (+, −, +) and f″ = 6x (− then +); f(−1) = 3 and f(1) = −1 ✓.
Step 3: 3x − x³ + 1 has the opposite signs of f′ (local minimum at −1), and x³ − 3x − 1 gives local values 1 and −3.
∴ f(x) = x³ − 3x + 1
Question 10Hard
f is a polynomial function of the third degree whose increasing, decreasing table shows: f′(x) > 0 on ]−∞, −2[, f′(x) < 0 on ]−2, 2[, f′(x) > 0 on ]2, ∞[, with f(−2) = 3 and f(2) = −1. How many points does the curve of f have in common with the x-axis?
Aone
Btwo
Cnone
Dthree
Show answer and explanation
Correct answer: (D) three
Explanation: Step 1: f(−2) = 3 is a local maximum value and f(2) = −1 is a local minimum value.
Step 2: On ]−∞, −2[ f increases (from −∞, as for any such cubic) up to 3, so it crosses the x-axis once; on ]−2, 2[ it decreases from 3 to −1, crossing once more.
Step 3: On ]2, ∞[ it increases from −1 without bound, crossing a third time.
∴ three points (the curve would meet the axis in only one point if both local values had the same sign).