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1-2 Higher derivatives of the function: practice questions

Pure Mathematics — Second: Differential & Integral Calculus · Mathematics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 36 questions on this lesson, each with an explanation.

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Question 1Easy

If y = cos 3x, find d²y/dx².

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Correct answer: (A) −9 cos 3x

Explanation: Step 1: y' = −3 sin 3x. Step 2: y'' = −9 cos 3x.

Question 2Easy

If f(x) = x⁴, find f''(x).

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Correct answer: (D) 12x²

Explanation: Step 1: f'(x) = 4x³. Step 2: Differentiate again: f''(x) = 12x². ∴ f''(x) = 12x².

Question 3Easy

If y = 3x⁵ − 2x³ + x, find d³y/dx³.

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Correct answer: (A) 180x² − 12

Explanation: Step 1: y' = 15x⁴ − 6x² + 1. Step 2: y'' = 60x³ − 12x. Step 3: y''' = 180x² − 12.

Question 4Medium

If y = sin x cos x, find the value of d³y/dx³ at x = 0.

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Correct answer: (B) −4

Explanation: Step 1: y = ½ sin 2x. Step 2: y' = cos 2x, y'' = −2 sin 2x, y''' = −4 cos 2x. Step 3: At x = 0: y''' = −4.

Question 5Medium

If y = x cos x, then d²y/dx² + y equals:

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Correct answer: (C) −2 sin x

Explanation: Step 1: y' = cos x − x sin x. Step 2: y'' = −sin x − sin x − x cos x = −2 sin x − x cos x. Step 3: y'' + y = −2 sin x − x cos x + x cos x = −2 sin x.

Question 6Medium

If x = sec θ and y = tan θ, find d²y/dx² at θ = π/4.

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Correct answer: (D) −1

Explanation: Step 1: dx/dθ = sec θ tan θ and dy/dθ = sec²θ, so dy/dx = sec θ/tan θ = csc θ. Step 2: d/dθ (csc θ) = −csc θ cot θ. Step 3: d²y/dx² = −csc θ cot θ ÷ (sec θ tan θ) = −cot³θ. Step 4: At θ = π/4: d²y/dx² = −1.

Question 7Medium

If f(x) = sin x, find f'''(x) (third derivative).

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Correct answer: (B) −cos x

Explanation: Step 1: f'(x) = cos x. Step 2: f''(x) = −sin x. Step 3: f'''(x) = −cos x. ∴ f'''(x) = −cos x.

Question 8Hard

If y = ax³ + bx², where a and b are constants, d³y/dx³ = 12 and the value of d²y/dx² at x = 1 is 10, find b.

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Correct answer: (C) −1

Explanation: Step 1: y' = 3ax² + 2bx, y'' = 6ax + 2b, y''' = 6a. Step 2: 6a = 12, so a = 2. Step 3: y''(1) = 6(2)(1) + 2b = 12 + 2b = 10, so b = −1.

Question 9Hard

If y = cot x, which of the following expresses d²y/dx² in terms of y?

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Correct answer: (D) 2y(1 + y²)

Explanation: Step 1: y' = −csc²x = −(1 + cot²x) = −(1 + y²). Step 2: y'' = −2y·y' = −2y·(−(1 + y²)) = 2y(1 + y²); −(1 + y²) is only the first derivative. ∴ 2y(1 + y²)

Question 10Hard

If x² + y² = 25, find the value of d²y/dx² at the point (3, 4).

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Correct answer: (C) −25/64

Explanation: Step 1: 2x + 2y y' = 0 ⇒ y' = −x/y = −3/4 at (3, 4). Step 2: y'' = −(y − x y')/y² = −(x² + y²)/y³ = −25/64 (−3/4 is only the first derivative). ∴ −25/64

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