2-1 The trigonometric form of a complex number: practice questions
Pure Mathematics — First: Algebra · Mathematics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 51 questions on this lesson, each with an explanation.
If Z = 4 e^((−π/3)i), then Z in the algebraic form x + yi is ..........
A2 + 2√3 i
B2√3 − 2i
C2 − 2√3 i
D−2 − 2√3 i
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Correct answer: (C) 2 − 2√3 i
Explanation: Step 1: r = 4, θ = −π/3, so Z = 4(cos(−π/3) + i sin(−π/3)).
Step 2: cos(−π/3) = 1/2 and sin(−π/3) = −√3/2.
Step 3: Z = 4(1/2 − (√3/2)i) = 2 − 2√3 i.
∴ Z = 2 − 2√3 i (2√3 − 2i swaps cos and sin).
What is the modulus of the complex number z = 3 + 4i ?
A√7
B7
C25
D5
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Correct answer: (D) 5
Explanation: Step 1: The modulus |z| = √(a² + b²) with a = 3 , b = 4
Step 2: |z| = √(3² + 4²) = √(9 + 16) = √25
∴ |z| = 5
Question 4Easy
What is the principal amplitude of z = √3 + i ?
Aπ/4
Bπ/3
Cπ/6
Dπ/2
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Correct answer: (C) π/6
Explanation: Step 1: z is in the first quadrant
Step 2: tan θ = b/a = 1/√3
Step 3: θ = tan⁻¹(1/√3) = 30° = π/6
∴ principal amplitude = π/6
Question 5Easy
What is the modulus of z = cos π/6 + i sin π/6 ?
Aπ/6
Bcos π/6
C√3/2
D1
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Correct answer: (D) 1
Explanation: Step 1: this is the trigonometric form r(cos θ + i sin θ) with r = 1
Step 2: for any angle θ , |cos θ + i sin θ| = √(cos²θ + sin²θ) = √1 = 1
∴ |z| = 1
Question 6Medium
Write z = -1 + i in trigonometric form.
A√2(cos π/3 + i sin π/3)
B2(cos 3π/4 + i sin 3π/4)
C√2(cos π/4 + i sin π/4)
D√2(cos 3π/4 + i sin 3π/4)
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Correct answer: (D) √2(cos 3π/4 + i sin 3π/4)
Explanation: Step 1: r = √((-1)² + 1²) = √2
Step 2: a = -1 (negative) , b = 1 (positive) so z is in the second quadrant
Step 3: the reference angle is tan⁻¹(1/1) = π/4 , so θ = π - π/4 = 3π/4
∴ z = √2(cos 3π/4 + i sin 3π/4)
Question 7Medium
If z1 = 8(cos 5π/6 + i sin 5π/6) and z2 = 2(cos π/6 + i sin π/6), find z1 ÷ z2 .
A4(cos 2π/3 + i sin 2π/3)
B16(cos 2π/3 + i sin 2π/3)
C4(cos π + i sin π)
D6(cos 2π/3 + i sin 2π/3)
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Correct answer: (A) 4(cos 2π/3 + i sin 2π/3)
Explanation: Step 1: divide the moduli and subtract the amplitudes: r = 8 ÷ 2 = 4 , θ = 5π/6 - π/6 = 4π/6 = 2π/3
Step 2: z1 ÷ z2 = 4(cos 2π/3 + i sin 2π/3)
∴ z1 ÷ z2 = 4(cos 2π/3 + i sin 2π/3)
Question 8Medium
The exponential form of the complex number Z = −√3 − i is ..........
A2 e^((π/6)i)
B2 e^((−5π/6)i)
C2 e^((5π/6)i)
D4 e^((−5π/6)i)
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Correct answer: (B) 2 e^((−5π/6)i)
Explanation: Step 1: r = √((−√3)² + (−1)²) = √4 = 2.
Step 2: x < 0, y < 0, so Z lies in the third quadrant: θ = −(π − π/6) = −5π/6.
Step 3: Z = r e^(θi) = 2 e^((−5π/6)i).
∴ 2 e^((−5π/6)i) (π/6 ignores the quadrant; 5π/6 is the amplitude of −√3 + i; 4 is r² not r).
Question 9Medium
If Z₁ = 6 e^((5π/6)i) and Z₂ = 3 e^((π/3)i), then Z₁ ÷ Z₂ = ..........
A2i
B−2i
C18i
D−√3 − i
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Correct answer: (A) 2i
Explanation: Step 1: Z₁/Z₂ = (r₁/r₂) e^((θ₁ − θ₂)i) = (6/3) e^((5π/6 − π/3)i).
Step 2: 5π/6 − π/3 = π/2, so Z₁/Z₂ = 2 e^((π/2)i).
Step 3: 2(cos π/2 + i sin π/2) = 2(0 + i) = 2i.
∴ Z₁ ÷ Z₂ = 2i (−2i subtracts the amplitudes the wrong way; −√3 − i adds them).
Question 10Hard
What is the principal amplitude of the complex number z = −2(cos 20° − i sin 20°)?
A−20°
B20°
C−160°
D160°
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Correct answer: (D) 160°
Explanation: Step 1: z = −2 cos 20° + 2i sin 20°, so x = −2 cos 20° is negative and y = 2 sin 20° is positive: z is in the second quadrant.
Step 2: −cos 20° = cos(180° − 20°) and sin 20° = sin(180° − 20°).
Step 3: z = 2(cos 160° + i sin 160°), with |z| = 2.
Step 4: The principal amplitude is 160°.