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2-1 The trigonometric form of a complex number: practice questions

Pure Mathematics — First: Algebra · Mathematics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 51 questions on this lesson, each with an explanation.

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Question 1Easy

If Z = 4 e^((−π/3)i), then Z in the algebraic form x + yi is ..........

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Correct answer: (C) 2 − 2√3 i

Explanation: Step 1: r = 4, θ = −π/3, so Z = 4(cos(−π/3) + i sin(−π/3)). Step 2: cos(−π/3) = 1/2 and sin(−π/3) = −√3/2. Step 3: Z = 4(1/2 − (√3/2)i) = 2 − 2√3 i. ∴ Z = 2 − 2√3 i (2√3 − 2i swaps cos and sin).

Question 2Easy

Find the modulus of z = 8 + 6i .

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Correct answer: (B) 10

Explanation: Step 1: |z| = √(8² + 6²) Step 2: = √(64 + 36) = √100 ∴ |z| = 10

Question 3Easy

What is the modulus of the complex number z = 3 + 4i ?

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Correct answer: (D) 5

Explanation: Step 1: The modulus |z| = √(a² + b²) with a = 3 , b = 4 Step 2: |z| = √(3² + 4²) = √(9 + 16) = √25 ∴ |z| = 5

Question 4Easy

What is the principal amplitude of z = √3 + i ?

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Correct answer: (C) π/6

Explanation: Step 1: z is in the first quadrant Step 2: tan θ = b/a = 1/√3 Step 3: θ = tan⁻¹(1/√3) = 30° = π/6 ∴ principal amplitude = π/6

Question 5Easy

What is the modulus of z = cos π/6 + i sin π/6 ?

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Correct answer: (D) 1

Explanation: Step 1: this is the trigonometric form r(cos θ + i sin θ) with r = 1 Step 2: for any angle θ , |cos θ + i sin θ| = √(cos²θ + sin²θ) = √1 = 1 ∴ |z| = 1

Question 6Medium

Write z = -1 + i in trigonometric form.

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Correct answer: (D) √2(cos 3π/4 + i sin 3π/4)

Explanation: Step 1: r = √((-1)² + 1²) = √2 Step 2: a = -1 (negative) , b = 1 (positive) so z is in the second quadrant Step 3: the reference angle is tan⁻¹(1/1) = π/4 , so θ = π - π/4 = 3π/4 ∴ z = √2(cos 3π/4 + i sin 3π/4)

Question 7Medium

If z1 = 8(cos 5π/6 + i sin 5π/6) and z2 = 2(cos π/6 + i sin π/6), find z1 ÷ z2 .

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Correct answer: (A) 4(cos 2π/3 + i sin 2π/3)

Explanation: Step 1: divide the moduli and subtract the amplitudes: r = 8 ÷ 2 = 4 , θ = 5π/6 - π/6 = 4π/6 = 2π/3 Step 2: z1 ÷ z2 = 4(cos 2π/3 + i sin 2π/3) ∴ z1 ÷ z2 = 4(cos 2π/3 + i sin 2π/3)

Question 8Medium

The exponential form of the complex number Z = −√3 − i is ..........

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Correct answer: (B) 2 e^((−5π/6)i)

Explanation: Step 1: r = √((−√3)² + (−1)²) = √4 = 2. Step 2: x < 0, y < 0, so Z lies in the third quadrant: θ = −(π − π/6) = −5π/6. Step 3: Z = r e^(θi) = 2 e^((−5π/6)i). ∴ 2 e^((−5π/6)i) (π/6 ignores the quadrant; 5π/6 is the amplitude of −√3 + i; 4 is r² not r).

Question 9Medium

If Z₁ = 6 e^((5π/6)i) and Z₂ = 3 e^((π/3)i), then Z₁ ÷ Z₂ = ..........

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Correct answer: (A) 2i

Explanation: Step 1: Z₁/Z₂ = (r₁/r₂) e^((θ₁ − θ₂)i) = (6/3) e^((5π/6 − π/3)i). Step 2: 5π/6 − π/3 = π/2, so Z₁/Z₂ = 2 e^((π/2)i). Step 3: 2(cos π/2 + i sin π/2) = 2(0 + i) = 2i. ∴ Z₁ ÷ Z₂ = 2i (−2i subtracts the amplitudes the wrong way; −√3 − i adds them).

Question 10Hard

What is the principal amplitude of the complex number z = −2(cos 20° − i sin 20°)?

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Correct answer: (D) 160°

Explanation: Step 1: z = −2 cos 20° + 2i sin 20°, so x = −2 cos 20° is negative and y = 2 sin 20° is positive: z is in the second quadrant. Step 2: −cos 20° = cos(180° − 20°) and sin 20° = sin(180° − 20°). Step 3: z = 2(cos 160° + i sin 160°), with |z| = 2. Step 4: The principal amplitude is 160°.

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