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Chapter Four · 1- Galvanic cells: practice questions

Chapter Four · Electrochemistry · Chemistry. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 155 questions on this lesson, each with an explanation.

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Question 1Easy

In an operating galvanic cell, reduction of the positive ions takes place at one of the two electrodes. This electrode is:

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Correct answer: (A) the cathode, which is the positive electrode.

Explanation: Reduction occurs at the cathode, which is the positive electrode in a galvanic cell.

Question 2Easy

What happens to the primary cells when the anode material is consumed and the ions of the cathode half-cell are diminished?

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Correct answer: (D) They stop to work as they are irreversible cells.

Explanation: This kind of cells stops to work when the anode material is consumed and the ions of the cathode half-cell are diminished, and it is impossible to be recharged making it an irreversible cell.

Question 3Easy

When two metals of different standard reduction potentials are combined to form a galvanic cell, the electrode that behaves as the cathode is the one having the:

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Correct answer: (D) Higher (more positive) standard reduction potential.

Explanation: The electrode with the more positive reduction potential is reduced and therefore acts as the cathode.

Question 4Medium

A clean strip of zinc is placed in copper(II) sulphate solution. Given E°(Zn²⁺/Zn) = -0.76 V and E°(Cu²⁺/Cu) = +0.34 V, which of the following is correct?

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Correct answer: (C) Zinc displaces copper because zinc is the stronger reducing agent, and the reaction is spontaneous.

Explanation: Zinc has the more negative E°, so it is oxidised and displaces copper spontaneously with a cell e.m.f. of +1.10 V.

Question 5Medium

Which of the following describes the components of the mercury cell poles and its electrolyte?

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Correct answer: (A) Zinc anode, mercury oxide positive pole, and potassium hydroxide electrolyte.

Explanation: In the mercury cell, the negative pole is zinc, the positive pole is from mercury oxide, and potassium hydroxide is used as an electrolyte.

Question 6Medium

A galvanic cell is formed from a nickel electrode and a silver electrode. Given E°(Ag⁺/Ag) = +0.80 V and E°(Ni²⁺/Ni) = -0.25 V, the standard e.m.f. of the cell equals:

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Correct answer: (A) +1.05 V

Explanation: Nickel (lower E°) is the anode, so E°cell = 0.80 - (-0.25) = +1.05 V.

Question 7Medium

Based on the electromotive series, which elements are considered good reducing agents?

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Correct answer: (A) The elements at the front of the series having high oxidation potential

Explanation: 3- The elements at the front of the series ( having high oxidation potential)are considered good reducing agents.

Question 8Hard

A galvanic cell is constructed from an aluminium electrode (E° = -1.66 V) and a zinc electrode (E° = -0.76 V) under standard conditions. Which of the following correctly identifies the anode and gives the standard e.m.f. of the cell?

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Correct answer: (D) Aluminium is the anode and the e.m.f. = +0.90 V

Explanation: Aluminium has the more negative potential so it is oxidised at the anode; e.m.f. = -0.76 - (-1.66) = +0.90 V.

Question 9Hard

Three metals A, B and C have standard reduction potentials A = -0.76 V, B = +0.34 V and C = -0.44 V. If three galvanic cells are made from the pairs (A, B), (B, C) and (A, C), which pair produces the cell with the greatest standard e.m.f.?

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Correct answer: (A) The pair (A, B), with e.m.f. = +1.10 V

Explanation: e.m.f. = E°(cathode) - E°(anode) is largest for the pair with the widest gap, (A, B): 0.34 - (-0.76) = +1.10 V.

Question 10Hard

In an electrolytic cell, why is the oxidation process forced to occur at the anode despite it being a non-spontaneous reaction?

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Correct answer: (B) Because the external power source pulls electrons from the anode.

Explanation: In electrolytic cells, an external source (like a dry cell) provides electrical energy to drive non-spontaneous redox reactions by extracting electrons from the anode.

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