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Chapter Two · Firstly: Qualitative chemical analysis: practice questions

Chapter Two · Chemical analysis · Chemistry. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 116 questions on this lesson, each with an explanation.

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Question 1Easy

In the detection of the sulphite anion, what is the observation when a paper wet with potassium dichromate acidified by sulphuric acid is exposed to the evolved gas?

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Correct answer: (C) The paper turns green

Explanation: Sulphur dioxide gas evolved turns a paper wet with potassium dichromate acidified by sulphuric acid to green.

Question 2Easy

In the classical scheme of cation analysis, which reagent is used as the group reagent to precipitate the cations of the first analytical group (such as Ag⁺ and Pb²⁺) as insoluble chlorides?

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Correct answer: (D) Dilute hydrochloric acid (dilute HCl)

Explanation: The first analytical group is precipitated as insoluble chlorides by dilute hydrochloric acid.

Question 3Easy

Which reagent is used to confirm the presence of sulphide (S²⁻) ions in a solution?

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Correct answer: (C) Silver nitrate solution.

Explanation: 'Salt solution + silver nitrate solution black ppt. is formed' as the confirmatory test for sulphide.

Question 4Medium

In the brown ring test for the nitrate ion, concentrated sulphuric acid is carefully poured down the side of the tube. The brown ring formed at the junction of the two liquids is due to the formation of:

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Correct answer: (C) the brown-ring compound FeSO₄.NO

Explanation: Part of the nitrate is reduced by iron(II) sulphate in the presence of conc. H₂SO₄, giving nitric oxide (NO). NO combines with FeSO₄ to form the brown-ring compound FeSO₄.NO at the junction of the two liquids.

Question 5Medium

Why is the qualitative analysis of a mixture more complex than that of a pure substance?

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Correct answer: (B) Because mixtures must first be separated into their components before identifying them using suitable indicators.

Explanation: If it is a mixture, firstly we must separate their component then identify them by the chemical method using suitable indicator.

Question 6Medium

A solution contains a single anion. It gives no precipitate with barium chloride, a white precipitate with silver nitrate that dissolves in concentrated ammonia, and no gas with dilute acid. The anion is the:

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Correct answer: (B) chloride ion

Explanation: No precipitate with BaCl₂ rules out sulphate; no gas with dilute acid rules out carbonate and sulphide; a white AgCl precipitate soluble in concentrated ammonia confirms the chloride ion.

Question 7Medium

Which of the following observations distinguishes a nitrite (NO₂⁻) from a nitrate (NO₃⁻)?

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Correct answer: (B) On adding dilute hydrochloric acid, only the nitrite evolves a colourless gas that turns reddish-brown at the mouth of the tube.

Explanation: The nitrite reacts with dilute HCl, giving colourless NO that turns reddish-brown at the mouth of the tube. The nitrate belongs to the conc. sulphuric acid group, and it is the nitrite (not the nitrate) that decolourises acidified permanganate.

Question 8Hard

Consider the following two reactions involving sodium thiosulphate: (1) reaction with dilute HCl yielding a yellow precipitate, and (2) reaction with iodine solution where the brown colour is removed producing sodium tetrathionate. Which species is specifically responsible for the yellow precipitate in the first reaction?

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Correct answer: (C) Suspended sulphur (S)

Explanation: For thiosulphate with HCl: 'Sulphur dioxide gas evolved and yellow ppt. as a result of suspend sulphur in solution'.

Question 9Hard

A solution contains a mixture of Fe³⁺ and Al³⁺ ions. Sodium hydroxide solution is added slowly until it is in large excess. Which of the following correctly describes the sequence of observations?

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Correct answer: (C) Both hydroxides precipitate; the white Al(OH)₃ dissolves in excess, leaving a reddish-brown Fe(OH)₃ precipitate

Explanation: Al(OH)₃ is amphoteric and dissolves in excess sodium hydroxide, while basic Fe(OH)₃ remains as a reddish-brown precipitate, allowing separation.

Question 10Hard

If you have an unknown solid inorganic salt and you add dilute hydrochloric acid, no gas evolves. Then you test a solution of the salt with silver nitrate solution, and it forms a yellow precipitate that is insoluble in ammonia solution. Which anion is most likely present?

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Correct answer: (A) Iodide (I¯)

Explanation: Under Iodide (I⁻) confirmatory test: Salt solution + silver nitrate solution yellow ppt. is formed from silver iodide insoluble in ammonia solution.

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