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Chapter 2 · Magnetic Effects of Electric Current and Measuring Instruments: practice questions

Unit 1 — Dynamic Electricity and Electromagnetism · Physics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 87 questions on this lesson, each with an explanation.

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Question 1Easy

Two long parallel straight wires carry electric currents in the same direction. The two wires:

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Correct answer: (A) attract each other

Explanation: Parallel currents flowing in the same direction attract each other, while currents in opposite directions repel.

Question 2Easy

A straight current‑carrying wire is placed parallel to the lines of a uniform magnetic field. The magnetic force acting on the wire is...

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Correct answer: (A) zero

Explanation: F = BIL sinθ and θ = 0 for a wire parallel to the field, so the force is zero.

Question 3Easy

In a moving-coil galvanometer the magnetic field is made radial by using a cylindrical soft-iron core between concave pole pieces. This is done so that:

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Correct answer: (C) the angle of deflection is directly proportional to the current for every position of the coil

Explanation: A radial field keeps the coil's plane always parallel to the field, so the torque equals NIAB and the deflection stays proportional to the current, giving a uniform scale.

Question 4Medium

A circular coil of 50 turns and radius 5 cm carries a current of 2 A. The magnetic flux density at its centre equals... (μ₀ = 4π×10⁻⁷ T·m/A)

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Correct answer: (C) 1.26×10⁻³ T

Explanation: B = μ₀NI/(2r) = (4π×10⁻⁷ × 50 × 2)/(2 × 0.05) = 4π×10⁻⁴ ≈ 1.26×10⁻³ T.

Question 5Medium

A horizontal straight wire carries a current directed towards the north and is placed in a uniform magnetic field directed vertically upwards. By Fleming's left‑hand rule, the magnetic force on the wire is directed towards the...

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Correct answer: (B) east

Explanation: With the current towards the north and the field vertically upward, F = IL × B points towards the east.

Question 6Medium

A long straight wire lies in the plane of the page and carries a conventional current directed to the right. The magnetic flux density at a point directly above the wire (in the plane of the page) is directed...

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Correct answer: (D) out of the page

Explanation: By the right‑hand rule, the field above a wire carrying current to the right points out of the page.

Question 7Medium

In a direct-current (DC) motor, the function of the split-ring commutator is to:

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Correct answer: (A) reverse the direction of the current in the coil every half revolution so that the coil keeps rotating in the same sense

Explanation: The commutator reverses the current in the coil each half turn, so the magnetic torque always acts in the same rotational sense and rotation is continuous.

Question 8Hard

A proton of mass 1.6 × 10⁻²⁷ kg and charge 1.6 × 10⁻¹⁹ C moves with a speed of 2 × 10⁵ m/s perpendicular to a uniform magnetic field of flux density 0.5 T. The radius of its circular path equals:

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Correct answer: (A) 4 × 10⁻³ m

Explanation: r = mv/(Bq) = (1.6×10⁻²⁷ × 2×10⁵)/(0.5 × 1.6×10⁻¹⁹) = 4 × 10⁻³ m.

Question 9Hard

A wire of fixed length is first wound into a single circular turn of radius (r) carrying a current (I), giving a flux density (B₁) at its centre. The same wire is then wound into two turns carrying the same current, giving (B₂) at its centre. The ratio B₂/B₁ equals...

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Correct answer: (C) 4/1

Explanation: The two‑turn coil has radius r/2, so B₂ = μ₀(2)I/(2·(r/2)) = 2μ₀I/r = 4 × B₁, where B₁ = μ₀I/(2r).

Question 10Hard

The magnetic flux density at a perpendicular distance of 2 cm from a long straight wire is 5×10⁻⁵ T. The current passing through the wire equals... (μ₀ = 4π×10⁻⁷ T·m/A)

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Correct answer: (C) 5 A

Explanation: From B = μ₀I/(2πd), I = B·2πd/μ₀ = (5×10⁻⁵ × 0.02)/(2×10⁻⁷) = 5 A.

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