Chapter 2 · Magnetic Effects of Electric Current and Measuring Instruments: practice questions
Unit 1 — Dynamic Electricity and Electromagnetism · Physics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 87 questions on this lesson, each with an explanation.
Two long parallel straight wires carry electric currents in the same direction. The two wires:
Aattract each other
Bexert no force on each other
Crotate about a common axis
Drepel each other
Show answer and explanation
Correct answer: (A) attract each other
Explanation: Parallel currents flowing in the same direction attract each other, while currents in opposite directions repel.
Question 2Easy
A straight current‑carrying wire is placed parallel to the lines of a uniform magnetic field. The magnetic force acting on the wire is...
Azero
Bequal to BI
Chalf its maximum value
Dmaximum and equals BIL
Show answer and explanation
Correct answer: (A) zero
Explanation: F = BIL sinθ and θ = 0 for a wire parallel to the field, so the force is zero.
Question 3Easy
In a moving-coil galvanometer the magnetic field is made radial by using a cylindrical soft-iron core between concave pole pieces. This is done so that:
Athe current through the coil is doubled
Bthe coil never rotates
Cthe angle of deflection is directly proportional to the current for every position of the coil
Dthe magnetic torque on the coil becomes zero
Show answer and explanation
Correct answer: (C) the angle of deflection is directly proportional to the current for every position of the coil
Explanation: A radial field keeps the coil's plane always parallel to the field, so the torque equals NIAB and the deflection stays proportional to the current, giving a uniform scale.
Question 4Medium
A circular coil of 50 turns and radius 5 cm carries a current of 2 A. The magnetic flux density at its centre equals... (μ₀ = 4π×10⁻⁷ T·m/A)
A6.28×10⁻⁴ T
B1.26×10⁻⁴ T
C1.26×10⁻³ T
D2.51×10⁻³ T
Show answer and explanation
Correct answer: (C) 1.26×10⁻³ T
Explanation: B = μ₀NI/(2r) = (4π×10⁻⁷ × 50 × 2)/(2 × 0.05) = 4π×10⁻⁴ ≈ 1.26×10⁻³ T.
Question 5Medium
A horizontal straight wire carries a current directed towards the north and is placed in a uniform magnetic field directed vertically upwards. By Fleming's left‑hand rule, the magnetic force on the wire is directed towards the...
Avertically downwards
Beast
Cwest
Dvertically upwards
Show answer and explanation
Correct answer: (B) east
Explanation: With the current towards the north and the field vertically upward, F = IL × B points towards the east.
Question 6Medium
A long straight wire lies in the plane of the page and carries a conventional current directed to the right. The magnetic flux density at a point directly above the wire (in the plane of the page) is directed...
Ato the left
Bto the right
Cinto the page
Dout of the page
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Correct answer: (D) out of the page
Explanation: By the right‑hand rule, the field above a wire carrying current to the right points out of the page.
Question 7Medium
In a direct-current (DC) motor, the function of the split-ring commutator is to:
Areverse the direction of the current in the coil every half revolution so that the coil keeps rotating in the same sense
Bincrease the current supplied to the coil
Cconvert alternating current into direct current before it enters the coil
Dproduce a radial magnetic field around the coil
Show answer and explanation
Correct answer: (A) reverse the direction of the current in the coil every half revolution so that the coil keeps rotating in the same sense
Explanation: The commutator reverses the current in the coil each half turn, so the magnetic torque always acts in the same rotational sense and rotation is continuous.
Question 8Hard
A proton of mass 1.6 × 10⁻²⁷ kg and charge 1.6 × 10⁻¹⁹ C moves with a speed of 2 × 10⁵ m/s perpendicular to a uniform magnetic field of flux density 0.5 T. The radius of its circular path equals:
A4 × 10⁻³ m
B2 × 10⁻³ m
C4 × 10⁻² m
D8 × 10⁻³ m
Show answer and explanation
Correct answer: (A) 4 × 10⁻³ m
Explanation: r = mv/(Bq) = (1.6×10⁻²⁷ × 2×10⁵)/(0.5 × 1.6×10⁻¹⁹) = 4 × 10⁻³ m.
Question 9Hard
A wire of fixed length is first wound into a single circular turn of radius (r) carrying a current (I), giving a flux density (B₁) at its centre. The same wire is then wound into two turns carrying the same current, giving (B₂) at its centre. The ratio B₂/B₁ equals...
A1/4
B2/1
C4/1
D1/2
Show answer and explanation
Correct answer: (C) 4/1
Explanation: The two‑turn coil has radius r/2, so B₂ = μ₀(2)I/(2·(r/2)) = 2μ₀I/r = 4 × B₁, where B₁ = μ₀I/(2r).
Question 10Hard
The magnetic flux density at a perpendicular distance of 2 cm from a long straight wire is 5×10⁻⁵ T. The current passing through the wire equals... (μ₀ = 4π×10⁻⁷ T·m/A)
A0.5 A
B2.5 A
C5 A
D10 A
Show answer and explanation
Correct answer: (C) 5 A
Explanation: From B = μ₀I/(2πd), I = B·2πd/μ₀ = (5×10⁻⁵ × 0.02)/(2×10⁻⁷) = 5 A.